∫OABC is a diamond, and∠ ∠COA=60?

∴△ABC is an equilateral triangle

∴∠CAB=60？

And ∵ D is on the AB side, and ∠C'DB'=60?

Point d coincides with point a.

B' and b are symmetric about x

∠∠COA =∠BAE = 60？ And OA=AB=2.

∴AE= 1,BE=√3

∴B(3, root number 3) ∴B'(3,- √3)

The inverse proportional function of ∴ intersection b' is y =-3 √ 3/x.

I hope it helps you. If you are satisfied, please adopt it! O(∩_∩)O