=(k+2) -8k squared
= the square of k-4k+4
= the square of k-2
Square of (k-2) ≥0
No matter what real number k takes, the equation always has a real number root.
(2) A root of the equation = (k+2)+(k-2) = k.
The other root of the equation =2 (k+2)-(k-2)=2.
Because one side of the isosceles triangle ABC is A > 1, and a=2.
So the perimeter of triangle ABC
c=k+2+2
=k+4
This question is correct. Please refer to. You use symbols to represent some words because I can't. )