It is 615 38 65106 (151) (210).

The rule of 613 27 49 ()121() is as follows.

6+7= 13

13+ 14=27

27+22=49

From their addends, the following laws are obtained (the addend is 7,14,22,)

7+7= 14

14+8=22

22+9=3 1

3 1+ 10=4 1

4 1+ 1 1=52

That is, the second number 13 should be added to 14 to get 13+ 14=27.

That is to say, the third number 27 should be added to 22 to get 27+22=49.

That is, the fourth number 49 should be added with 3 1 to get 49+3 1=80.

That is, the fifth number 80 should be added to 4 1 to get 80+4 1= 12 1.

That is, the sixth number 12 1 is added to 52 to get121+52 =173.

That is, the initial addend is 7, followed by 8,9, 10,1,12, 13, 14, 15,/kloc-0. ..........

So it is 613 27 49 (80)121(173).

The rules of 6 15 38 65 106 () are as follows

6+9= 15

15+23=38

38+27=65

65+4 1= 106

From their addends, we can get the following laws (addends are 9, 23, 27, 4 1,)

9+ 14=23

23+4=27

27+ 14=4 1

4 1+4=45

45+ 14=59

59+4=63

That is, the second number 15 should be added with 23 to get 15+23=38.

That is to say, the third number 38 should be added to 27 to get 38+27=65.

That is, the fourth number 65 should be added to 4 1 to get 65+4 1= 106.

That is, the fifth number 106 should be added to 45 to get106+45 =151.

That is, the sixth number 15 1 is added to 59 to get151+59 = 210.

So it is 615 38 65106 (151) (210).