Solution: ∫ Known ∠ ABC = ∠ DCB, and BC = CB.
∴ If ① ∠ A = ∠ D is added, △ ABC △ DCB can be determined by AAS;
If 2AC = DB is added, it belongs to the angular order, and it is impossible to judge △ ABC △ DCB;
If 3AB = DC is added, which belongs to the angular order, it can be judged as △ ABC △ DCB.
So the answer is: ②.