△ area of △ADP =a*2/2=2 a=2

The inverse proportional function y=k/x passes through point A and replaces point A..

2=k/- 1 k=-2

So the inverse proportional function:

y=-2/x

While the proportional function passes through point A, let the proportional function be y=kx.

2=-k k=-2

So the proportional function:

y=-2x

2. Let P(m, n)

△ADP area = 2 * |- 1-m |/2 = 4。

M=-5 or m=3

Point p is on the inverse proportional function.

N=2/5 or n=-2/3

So point P is (-5,2/5) or (3,2/3).