(1) When the cylinder is placed horizontally, the pressure of the enclosed gas is p1= P0 =1×105 (PA), the temperature is T 1=300K, and the volume is v1= 24cm.

When the steel cylinder is placed vertically, the pressure of the enclosed gas is p2 = P0+MGS =1.2×105pa, the temperature is T2=T 1=300K, and the volume is V2 = hs.

According to the ideal gas state equation, p1v1t1= p2v2t2.

Substituting the data can get H=20cm.

(2) Assuming that the piston can reach Dhaka Ring, the meaning of this question is:

T3=675KV3=36cm×S？ According to the ideal gas state equation, there are:

p 1v 1t 1 = p3v 3t 3

Substituting the data, we can get P3 = 1.5× 105pa, so assuming that the piston can reach the snap ring, the gas pressure is P3 = 1.5× 105pa.

Answer: (1) The distance from the piston to the bottom of the cylinder is 20cm；;

(2) When heated to 675K, the pressure of closed gas is 1.5× 105 Pa.