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Math problem Three monkeys went up the mountain to pick peaches. They picked 46 peaches. One monkey picks twice as many as two, at least three, but more than five. How many did everyone choose?
Because three monkeys pick more than five, it is impossible for one monkey and two monkeys to pick 4 1 each, but the total number of peaches picked by one monkey and two monkeys must be a multiple of 3, so it can only be 39, 36, 33 or less.

If it is 39, then one monkey chooses 26, two monkeys choose 13, and three monkeys choose 7.

If it is 36, then one monkey chooses 24, two monkeys choose 12 and three monkeys choose 10.

If it is 33, then one monkey chooses 22, two monkeys choose 1 1, and three monkeys choose 13, which does not meet the meaning of the question.

Even less.

So the answer is 26 for one monkey, 13 for two monkeys, 7 for three monkeys or 24 for one monkey, 12 for two monkeys and 10 for three monkeys.