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Geometric problems about coordinate axes in junior middle school mathematics
( 1)s⊿aob= 1/2▏oa▏×▏yb▏= 1/2×4×2= 1

(2) Taking AC as the diagonal, the midpoint of AC (5/2, 1/2) is obtained by the midpoint formula.

(x+2)/2=5/2 x=3

﹛ =>﹛

(y-2)/2= 1/2 y=3

(3) B as BF∨X axis, Y axis in F, and then EF∨AB as X axis in E.

∴ e (2,0),F(0,2)。 Or e (-2,0), f (0 0,2)