Solution, the acceleration of a and b: AA = AB = GSIN 37? μgcos37 =2m/s2,
The time from ball a to point c is sa = h1sin37 =12aata2? tA=2h 1aAsin37 =3? s,
The time from ball B to point C is: Sb = H2SiN37 = 12ABTB2? tB=2h2aBsin37 = 1? s,
The balls A and B will not collide on the inclined plane, and the longest t is: t = ta-TB = 2s;;
(2) The speed of the ball from point A to point C is vA=aAtA=6m/s,
Let a catch up with b at time t, then: vA(t? tA)= 12at2,
T≤vAa,
Solution: a≤ 1m/s2,
That is, b-ball acceleration a? The maximum shall not exceed1m/S2;
Answer: (1) In order to ensure that ball A and ball B will not collide on the inclined plane, the maximum length of T should not exceed 2s.
(2)B ball acceleration a? When the maximum cannot exceed 1m/s2, ball A may catch up with ball B. 。
In teaching practice, I designed a table of fractional lines according to the "division and combination" of one-year series, and discussed it with th