In the regular quadrangular prism ABCD-a1b1c1d1,

∵AA 1⊥ planar ABCD, AD? ≠ Plane ABCD,

∴AA 1⊥AD, so AA 1 = 13? 4 = 3, …(3 points)

∴ The volume of a regular quadrangular prism is (22) × 3 = 12...(6 points)

(2) Let G be the midpoint of the edge AD, connected with ge and GB, in △A 1AD,

∫E and g are the midpoint of line segment A 1D and AD, respectively.

∴EG∥A 1A and eg = 12aa 1 = 32,

∴∠GEB is the angle formed by non-planar straight line AA 1 and BE. ... (8 points)

∵A 1A⊥ plane ABCD, GB? ≠ plane ABCD, ∴AA 1⊥GB,

And eg∑a 1a, ∴EG⊥BG, ... …( 10/0)

GE = 32，BG= 1+22=5，

∴ tan ∠ geb = bgge = 532 = 235, so ∠ geb = arctan2 is praised and stepped on. What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Recommend lawyer service: If your problem has not been solved, please describe your problem in detail. Free professional consultation on other similar questions through Baidu Pro 2010-1-15 It is known that the bottom of the quadrangular prism ABCD-a1b1c1d1is To find the volume C 1-ABF 20 12-08-23 of a triangular pyramid, it is known that in a quadrilateral prism ABCD-a1b1c1d1,the base length AB = 2 and the side length ab = 2. 9 March 9, 2020, as shown in figure B1C. It is known that in the regular quadrangular prism ABCD-A1B1D1,the side length of the bottom surface is A and the side length is 2a, so we can find 320 16- 12. As shown in the figure, in the O-ABCD of a quadrangular cone, the bottom ABCD is a square with a side length of 2, OA⊥ bottom ABCD, OA=2, and m is 8201-08-15 of OA. The regular quadrangular prism ABCD-A 1b6555 is known. Side length √2520 13-05-09. It is known that the base length of the regular quadrilateral ABCD-a1b1d1is 2, and A 1D= radical sign 13. Find the volume of a regular quadrilateral. It is known that in the regular quadrangular prism ABCD-a1b1c1d1,the side length of the bottom surface is a and the side length is 2a, so find 520 17-09-08(20 13 As shown in the figure, in the regular triangular prism ABC-a1b1c1,AA 1=6, and the angle formed by the non-planar straight line BC 1 and AA 1 is π6. How to solve four similar problems of this triangular prism? & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? What impact will the "network toilet" have? The price of electric cars has dropped many times. Is the quality guaranteed? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720033570；