Original formula =(2×4√3-3×3√3)/(√6)

=-√3/√6

=- 1/√2

=-√2/2

B Original formula = 2 (√ 2+1)/(√ 2+1)+2 (√ 3+1)/(√ 3+1) (√ 3

=2√2+2+√3+ 1

=2√2+√3+3

C original formula = √ 5a× 10a = √ 50a 2 = 5a √ 2.

D Original formula =√3a-√2a?

If a is not under the root symbol.

(√3-√2)a

I can't forget it.

This is the simplest.

If you don't understand, please ask. Have a good time O(∩_∩)O~