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What are the judgments about similar triangles in junior high school mathematics? Specifically, and their abbreviations.
Ad⊥bc of d,ce⊥ab

Therefore: ∠bad=90-∠b,

∠bce=90-∠b

So: ∠bad=∠bce

∠ ADB =∠ CDG = 90,

ab=cg

Therefore: △ Abd△ CGD

(aas)

So: AD = CD (congruent triangles has equal sides).

△ in △acd

,∠adc=90

So: ∠ ACD = 45, which means ∠ ACB = 45.