M={y|- 1≤y≤ 1}、N = { x |- 1 & lt; x & lt 1}
m∩N = { x |- 1 & lt; x & lt 1}
Since x is a real number, the modulus of x-I is:
|x-i|=√(x? + 1)
Then:
| x-I | & lt; √2
√(x? + 1)& lt; √2
x? + 1 & lt; 2
x? & lt 1
Then:
- 1 & lt; x & lt 1
Namely: n = {x |- 1