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Junior high school mathematics application problem (fractional equation)
Solution: Suppose B sells X yuan per box, then A sells (x+ 10) yuan per box, and if A enters Y box, then B enters (25-y) box.

According to the meaning of the problem, the equation is obtained:

(x+ 10)*y= 1000 ①

x*(25-y)= 1000+350 ②

Get from (1)

y= 1000/(x+ 10) ③

Substitute ③ into ② to get.

x *[25- 1000/(x+ 10)]= 1350

arrange

25x^2-2 100x- 13500=0

Get a solution

x 1=90

X2=-6 (irrelevant, omitted. )

Substitute x≈8 1 into ③.

y= 1000/(90+ 10)

y= 10

25- 10= 15 (box)

That is, if A inputs 10 boxes of drinks, then B inputs 15 boxes of drinks.