If the solution set of inequality x > a, x > 1 is x > 1, the key point of factorization is to be able to distinguish square difference formulas with polynomials at the beginning and end in a completely flat way, and also to use quadratic trinomial multiplication formula x 2+(a+b) x+ab = (x+a) (x
Hope to adopt, don't be lazy, and the answer is complete before it can be adopted or recommended ~