Question 1: Let the speed of the first car be x and the speed of the second car be y, and the equation10x+10y = 819x+5x+5y = 810.

So X=45 Y=36.

Question 2: The person who goes to B is the (20-X) person who goes to A according to the equation.

So there are 27+X=2( 19+20-X), 17 to get X= 17, and 3 to B.

Question 3: Let Xiaoming make X racks and Xiao Zhang make Y racks 2x+2x+2y = 418+23y+3y+3x = 418+32 every day.

So we get X=90 Y=30.

Question 4: the deadline is x hours and the task is part y.

10x = y-311(x-1) = y, so we get X= 14 Y= 143. All right, you're welcome.