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Mathematical problems in calculating volume and capacity
Solution: subtract the volume of the cone to get the truncated cone.

The height of the big cone can be obtained from the proportional relation of the central axis:

For 10/20=h/(8.5+h), H=8.5.

Height = 8.5+ height =28.875

Large cone volume = 3.14 * (20/2) 2 *17/3 =1779.333.

Cone volume = 3.14 * (10/2) 2 * 8.5/3 = 214.567.

Volume =1779.333-214.567 =1556.767 cubic centimeters.

13 *13 * 3.14 * 535/4 = 70975.78 cubic centimeters.