Let the high straight line passing through point B be 7x-2y- 1=0.
Let AC linear equation y =-2/7x+m.
(3,4) Substitute the solution to get y=-2/7x+34/7.
That is 2x+7y-34=0.
Similarly, the AB equation y=-7/2x+29/2, that is, 7x+2y-29=0.
solve an equation
7x-2y- 1=0
7x+2y-29=0
Get the b coordinate (15/7,7)
solve an equation
2x-7y-6=0
2x+7y-34=0
Get the coordinates of point C (10,2).
Let BC equation y=ax+b
Substitute b
C =-7/11x+92/1/y at two points.
That is 7x+ 1 1y-92=0.