Let the high straight line passing through point B be 7x-2y- 1=0.

Let AC linear equation y =-2/7x+m.

(3,4) Substitute the solution to get y=-2/7x+34/7.

That is 2x+7y-34=0.

Similarly, the AB equation y=-7/2x+29/2, that is, 7x+2y-29=0.

solve an equation

7x-2y- 1=0

7x+2y-29=0

Get the b coordinate (15/7,7)

solve an equation

2x-7y-6=0

2x+7y-34=0

Get the coordinates of point C (10,2).

Let BC equation y=ax+b

Substitute b

C =-7/11x+92/1/y at two points.

That is 7x+ 1 1y-92=0.