Solution: A run 1 lap needs 14 hours, B run 1 lap needs 18 hours, C run 1 lap needs/4 hours, D run 1 lap needs/kloc.

The least common multiple of 14, 18, 16, 1 12 is12;

In other words, the four of them met again after 12 hours.

At this time, four people * * * ran away12× (4+8+6+12) =15 (km);

A: From the time of departure to the time when the four people met again, the four people ran15km.