X * (x+1) * (x+2) * (x+3)+1,we are looking at 5*5,1*1,/kloc.

(1+ 1)+1 squared = 5 (2+1)+2 =11(36+1)+36 = 65436.

Therefore, it can be concluded.

X * (x+1) * (x+2) * (x+3)+1= [(x+1) squared +x]*[(x+ 1) squared +x].

By decomposing x * (x+1) * (x+2) * (x+3)+1,we can get

x^4+6x^3+ 1 1x^2+6x+ 1。

Factorizing [(x+1) square+x] * [(x+1) square+x] can get the same result, that is

(x to the 4th power) plus (6x to the 3rd power) plus (1 1x squared) plus (6x) plus 1.

We can get it by bringing a set of numbers into a topic at random.

2 * (2+1) * (2+2) * (2+3)+1= [(2+1) squared +2]*[(2+ 1) squared +2].

12 1= 12 1

(because I can't get into the square of x several times, it's a bit messy. If you take your time, you should be able to see clearly. The result is definitely no problem)