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Three math college entrance examination questions ... please help explain. Thank you! ! Any topic will do. Thank you.
1. Connect OE, that is, the center line of △CAP-> OE‖PA.

-& gt； The angle formed by non-planar straight line PA and BE =∠OEB.

△ in△ PBC: COSC = (BC/2)/PC = √ 2/4.

△ In△ △EBC: Really? =BC？ +CE？ -2BC * BEcosC = 2+ 1- 1 = 2

△OBE: 0b = 1, OE = PA/2 = 1, BE = √ 2-> △OBE isosceles right triangle.

-& gt； The angle formed by non-planar straight line PA and BE = ∠ OEB = 45.

2.0-0.5x Root Number 2

3. The intersection can be A(c, 3c/2) and substituted into hyperbolic equation, and C 2-A 2 can be used instead of B 2 to solve the equation about E 2.

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