Solution: Make an equilateral triangle BCF with BC as the side to the left, connect EF, and make an equilateral triangle EFG with EF as the side to connect AG, AF and DF.

So CF=CB=BF

Angle CFB= Angle BCF= Angle CBF=60 degrees.

FE=FG=EG

Angle EFG= Angle EGF= Angle FEG=60 degrees.

Because the angle CAE= 10 degrees

Angle BAE=70 degrees

So angle CAB= angle CAE, ten angles BAE= 10, and ten angles 70=80 degrees.

Because the angle CBD=20 degrees

Angle ABD=60 degrees

So angle CBA= angle CBD, ten angles ABD=20, 60=80 degrees.

So angle CAB= angle CBA=80 degrees.

So CA=CB

So BF=CA

CF=CA

So angle CFA= angle CAF

Because the angle of the cab is ten degrees, CBA is ten degrees and ACB is 180 degrees.

So ACB angle =20 degrees.

So ACB angle CBD angle =20 degrees.

So CD=BD

Because DF=DF

CF=BC (certification)

So triangle CDF and triangle BDF are congruent (SSS)

So angle CFD= angle BFD= 1/2 angle CFB=30 degrees.

Because angle ACF= angle BCF and angle ACB=60-20=40 degrees.

So angle ADF= angle ACF, decagonal CFD=40, and decagonal -30=70 degrees.

Because the angle CAF has ten angles CFA has ten angles ACF= 180 degrees.

So angle CAF= angle CFA=70 degrees.

So angle ADF= angle CAF=70 degrees.

So DF=AF

Because the angle ADF has ten angles CAF has ten angles AFD= 180 degrees.

So the angle AFD=40 degrees

Because angle BFA= angle CFA, one corner CFB=70-60= 10 degrees.

So angle BFA= angle CAE= 10 degrees.

Because angle ABF= angle CBA corner CBF=80-60=20 degrees.

So ABF angle = ACB angle =20 degrees.

Because BF=CA (authentication)

So triangle ABF and triangle ECA are congruent (ASA)

So AF=AE

So angel ·AFE = angel ·AEF

Because angle EAF= angle CAF = ten angles CAE= 10 ten 70=80 degrees.

Angle AFE decagon AEF decagon EAF= 180 degrees.

So AEF angle = AFE angle =50 degrees.

Because FG=EG (authentication)

AF=AE (authentication)

AG=AG

So triangle AGF and triangle AGE are congruent (SSS)

So the angle AGF= 1/2 and the angle EGF=30 degrees.

Because angle AFG= angle EFG, AFE=60-50= 10 degrees.

Angle DFE= angle AFE, angle AFD=50-40= 10 degree.

So the angle AFG= the angle DFE= 10 degrees.

FG=FE (certification)

AF=DF (authentication)

So triangle AFG and triangle DFE are congruent (SAS).

So angle AGF= angle DEF=30 degrees.

Because DEA= DEF=50-30=20 degrees.

Angle DEA=x

So x=20 degrees.