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Senior three mathematics analytic geometry courseware 20 18. Two-mode mathematics in senior three 12.
Ha no.3 middle school, hyperbolic problem.

Since it is an arbitrary point, let s be the vertex of hyperbola, then s, m, n, m, n coincide, and OP=OQ. Because (1/om+1/on) (op+OQ) ≥ 4, 2OP×2/OM≥4 and OP≥OM. And because MP is parallel to. /a？ )=√((a？ +b？ )/a？ )≥√(2a？ /a？ ) =√2. So the range of hyperbola eccentricity is e∈[√2, +∞).

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