Solution: As shown in the figure, point A and point B are perpendicular to the alignment line, and the alignment line is at point E and point D respectively. If |BF|=a, it is known as |BC|=2a and defined as |BD|=a, so ∠ BCD = 30.

In the right triangle ACE, | AE | = 3, |AC|=3+3a,

∴2|AE|=|AC|

∴3+3a=6，

So a= 1,

∫BD∨FG，

∴ 1/p=2/3？ Find p=3/2,

So the parabolic equation is y? =3x。