Unit 2 math problems in the second volume of the sixth grade - Training Enrollment Network

Unit 2 math problems in the second volume of the sixth grade

The surface area is equal to the bottom area+lateral area.

The diameter of the bottom surface is 3dm, and the height is 5dm1.5x0/.5xπ+(3π× 5) =17.25xπ ≈ 54.165dm.

Diameter 8 cm, height16 cm: 4× 4× π+(8 π×16) =144× π ≈ 452.16 cm.

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The state regarded as a particle.