Get m=-2? 1=2,

That is, the coordinates of point A are: (-1, 2),

∫S△ABP = 12PB？ Associated press,

∴2= 12PB×2，

∴PB=2，

∴ point b (1, 0);

Let the analytical formula of straight line AB be y=kx+b(k≠0),

Substitute the coordinates of point A and point B into 0 = k+B2 =? k+b，

Solution: k =? 1b= 1，

Therefore, the analytical formula of straight line AB is y =-x+1;

(2)∵ Points A (- 1, 2) and B (1, 0),

∴OA=5，AB = 22。 As shown in the figure:

When the point C is on the positive semi-axis of the X axis,

∠∠ACO =∠BAO，∠AOC=∠BOA，

∴△OAC∽△OBA，

∴OAOC=OBOA，

∴5OC= 15，

∴OC=5，

That is, point c1(5,0);

When the point C is on the negative semi-axis of the X axis,

∠∠ACO =∠BAO，∠ABC=∠OBA，

∴△ABO∽△CBA，

∴ABCB=OBAB，

∴8CB= 18，

∴CB=8，

That is, point C2 (-7,0).

To sum up, the coordinates of point C are: (5,0), (-7,0).