x+2*y= 12

2*x+3*y=2 1

Just solve the equation.

The solution is x=6 and y=3.

2. Set up m skilled workers, recruit n new workers, and only need to assemble 30 cars every month (so 360 cars are assembled a year).

6*m+3*n=30

Binary linear equation, the title says that according to the discussion on the number of transferred skilled workers, let's discuss the value of m.

m=0，n= 10

m= 1，n=8

m=2，n=6

m=3，n=4

m=4，n=2

m=5，n=0

The above are different schemes for transferring skilled workers and recruiting new workers (m=0, n=0).

3. First of all, we should meet the needs of new workers more than skilled workers, that is,

m=0，n= 10

m= 1，n=8

m=2，n=6

m=3，n=4

In these cases, the total wages are calculated separately.

( 1)S = 1200 * 10 = 12000

(2)S = 2000+ 1200 * 8 = 1 1600

(3)S = 2000 * 2+ 1200 * 6 = 1 1200

④S = 2000 * 3+ 1200 * 4 = 10800

Therefore, the solution to the problem is (4):3 skilled workers and 4 new workers.

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