(x+2)(x+7)/(x+7)+(x+7)(x+2)/(x+2)=(x+3)(x+6)/(x+6)+(x+6)(x+3)/(x+3)
(x+2)(x+7)/(2x+9)=(x+3)(x+6)/(2x+9)
When 2x+9=0, there is x=-2/9.
When 2x+9≠0, there is
(x+2)(x+7)=(x+3)(x+6)
x^2+9x+ 14=x^2+9x+ 18
No answer
So x=-2/9
(x+2)/(x+3)+(x+3)/(x+4)=(x+4)/(x+5)+(x+ 1)/(x+2)
(x+2)/(x+3)-(x+ 1)/(x+2)=(x+4)/(x+5)-(x+3)/(x+4)
(x+2)(x+ 1)/(x+ 1)(x+3)-(x+2)(x+ 1)/(x+2)(x+2)=(x+4)(x+3)/(x+5)(x+3)-(x+4)(x+3)/(x+4)(x+4)
(x+2)(x+ 1)/[(x^2+4x+3)-(x^2+4x+4)]=(x+4)(x+3)/[(x^2+8x+ 15)-(x^2+8x+ 16)]
(x+2)(x+ 1)/(- 1)=(x+4)(x+3)/(- 1)
(x+2)(x+ 1)=(x+4)(x+3)
x^2+3x+2=x^2+7x+ 12
4x=- 10
x=-2/5