Current location - Training Enrollment Network - Mathematics courses - Congcong math teacher
Congcong math teacher
Let's assume that Cong Cong is right in the X lane and wrong in the 20-x lane.

Obviously in the Y lane, the wrong 20Y lane.

Obviously 20≥x & gt;; y≥0

According to the meaning of the question:

Xm-(20-x)n=3 15 is simplified as x(m+n)=3 15+20n (1).

Ym-(20-y)n=56 is simplified as y(m+n)=56+20n (2).

The two formulas are subtracted to get (x-y)(m+n)=259 and 259=7x37.

From the range of values of x and y, we can know that x-y=7 m+n=37.

For formula (2), substituting m+n=37 shows that:

The mantissa of the right 20n must be 0, so the mantissa of the right result is 6.

On the left is 37y, and the last number is 6, so it can only be y=8 within 20, if y= 18, x =18+7 > 20

So x= 15, y=8.

Substituting the original equation can get the following results:

m=25 n= 12