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The answers to supplementary exercises 56-57 of mathematics in the first volume of the sixth grade of primary school.
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P56 page

1, nine sixteenth; Seven sixteenth

2. One fifth; One-half; Three tenth

3,5+3 = 8 Fruit candy: 64÷8×5=40 (kg) Chocolate: 64÷8×3=24 (kg)

4. The ratio of Class A to Class B is 42: 36 = (42 ÷ 6): (36 ÷ 6) = 7: 67+6 =13130 ÷13× 7 = 70 (.

5,3+3+2 = 8 40 ÷ 8 = 5 (cm) 5×3= 15 (cm) 5×3= 15 (cm) 5×2= 10 (cm)

P57 page

1,1+2+3 = 6 180÷ 6×1= 30 (degrees) 180÷6×2=60 (degrees)/kloc-

2.( 1)25×25=625 (g) (2) 1000÷25× 1=40 (g)

3,5+2 = 7 35÷7×5 = 25(a)35÷7×2 = 10(a)25- 10 = 15(a)

4, 60/5= 12 (box) -60 kg of toffee can be matched with 12 box.

60- 12*3=24 (Jin)-The sugar is used up, leaving 24 Jin of chocolate.

60/3=20 (box)-60 kilograms of chocolate can be matched with 20 boxes.

20*5= 100 (kg) -60 kg of chocolate needed 100 kg of toffee.

100-60=40 (kg) -40 kg toffee, you can use up all the chocolate.

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