You need to know what the smallest simplification it can cut down is. These minimizations are numbers that are not divisible by numbers other than themselves and 1. Then multiply these minimized simplifications to get all its divisors respectively. By the way, it and 1 are also its divisors.

For example, if you recite the multiplication formula, you will know that only 2 and 5 can be divisible by 10, and both 2 and 5 can be divisible by other numbers except itself and 1, so the divisor of 10 is 1, 2,5,/kloc.

Another example is 60, and the minimization numbers are 2, 2, 3 and 5 respectively. Then, 2 * 2 = 4, 2 * 3 = 6, 2 * 5 = 10, 3 * 5 = 15, 2 * 2 * 3 = 12, 2 * are respectively.

So all the divisors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 30, 60.