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[Junior High School Mathematics] On the Calculation of Trigonometric Functions
1.

Introducing numerical value

√((3-2√2)/4)

3-2√2= 1-2√2+2=( 1-√2)?

So √((3-2√2)/4)=((√2)- 1)/2.

2.

Introducing numerical value

√((2-√3)/2)

Use *2 up and down to get √((4-2√3)/4).

4-2√3= 1-2√3+3=( 1-√3)?

So √((2-√3)/2)=((√3)- 1)/2.

Open Roots of 1 and 2

think

It's a formula, so be careful when you root it.

sign symbol

Judgment of ...

3.BD=2,CD=6,

AD? =BD*CD,

AD=2√3

The rest is simple, tanC=AD/CD=(√3)/3.