(2)∵y increases with the increase of x ∴a> 0. Again ∵ ab

2 (1) Let the analytical formula of linear function be y = kx+B, and substitute A(-2, -3) b (1, 3) into the analytical formula, and we get-3 = k (-2)+b.

3=k* 1+b

K = 2 b = 1。 The analytical formula of ∴ linear function is y=2x+ 1.

(2) When x=- 1, y = 2x+1= 2 * (1)+1=-1. Therefore, p(- 1.

3 If the image intersects the Y axis at point P, the abscissa of point P must be 0. Substitute x=0 into y=kx+b to get y=b, so p(0, b). Similarly, we can find Q (0 0,3). ∵ Q (0 0,3) and p (0,b) are symmetric about x, ∴ b = ∴ equation -2=k*5-3 k= 1/5. Therefore, the analytical formula of linear function is y=x/5-3.

4: The intersection of the image and the Y axis is above the X axis ∴k- 1> 0k & gt； 1. and ∵y decrease ∴ 2k-3

So 1