( 1)
7/(x+2)= 1-3x/(x+2)-2
Multiply left and right by x+2, and you get
7= 1-3X-2(X+2)
7= 1-3X-2X-4
10=-5X
X=-2
After testing, when x=-2, the denominator is 0.
So x=-2 is to grow roots and abandon roots.
So the equation has no solution.
(2)
x-2/x-3= 1- 1/3-x
Multiply left and right by x-3, and you get
x-2=x-3+ 1
-2=-2 hold.
X≠3 is obtained from denominator 3-x≠0.
So the solution of the original equation is an arbitrary number of x≠3.