Two mathematical solutions to the equation of senior two are urgent! ! ! ! !

Solution:

( 1)

7/(x+2)= 1-3x/(x+2)-2

Multiply left and right by x+2, and you get

7= 1-3X-2(X+2)

7= 1-3X-2X-4

10=-5X

X=-2

After testing, when x=-2, the denominator is 0.

So x=-2 is to grow roots and abandon roots.

So the equation has no solution.

(2)

x-2/x-3= 1- 1/3-x

Multiply left and right by x-3, and you get

x-2=x-3+ 1

-2=-2 hold.

X≠3 is obtained from denominator 3-x≠0.

So the solution of the original equation is an arbitrary number of x≠3.