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CRB in mathematics
It will be more intuitive and accurate to draw a few axes to solve this kind of problem, but it is not convenient to draw here. I will try my best to make it clear.

Solution: Because x∈Z is not emphasized in both sets A and B, it cannot be considered that A = {3 3,4,5,6 6} B = {2 2,3,4,5,6,7,8,9}.

When drawing a number axis, you only need to draw A and B on the same number axis. Pay attention to draw a solid circle with equal size and a hollow circle with unequal size when drawing the end point.

It can be directly calculated from CR(A∩B)={x x≤2 or x≥ 10} on the number axis.

CR(A∪B)= { x x & lt; 3 or x≥7}

(CRA)∩B = { x ^ 2 & lt; X<3 or 7 ≤ x

A ∨( CRB)= {x x≤2 or 3 ≤ X.