Junior high school mathematical geometry problem (circle) for master solution! ! The topic is as follows

Solution: connect BO, do OE vertical BC through point O, and connect AO. Post office

Let the radius be x.

Because OE is perpendicular to BC

So BE=CE=4.

therefore

PE=6

In the right triangle BOE, Pythagoras concludes that the square of OE = the square of Bo-the square of Be.

So the square of OE = the square of x-16.

In the Rt triangle POE, Pythagoras obtains: the square of PO = the square of OE+the square of PE.

So the square of PO = X- 16+36 square.

In the Rt triangle APO, Pythagoras obtains: the square of PO = the square of AO+the square of AP.

So the square of X- 16+36 = the square of x+the square of AP.

(The square of the X side of Equation 2 is rounded)

Solution: AP=2 radical number 5