Current location - Training Enrollment Network - Mathematics courses - 20 Methods of Solving Mathematics Problems in the Fifth Grade of Primary School
20 Methods of Solving Mathematics Problems in the Fifth Grade of Primary School
PS: Typing is so tiring that I can only write these 1. The school covers an area of a rectangle, with a length of 100 m and a width of 70 m. Poplars should be planted around the school. If the distance between every two poplars is 10 meter, how many poplars can be planted around the school? (100+70)×2÷ 10=34 (trees) A: 34 poplars can be planted around the school. 2. In the fifth grade, 195 people went for a spring outing. When they came to the car company to rent a car, they found that each minibus 120 yuan could accommodate 30 people. The bus doesn't work 150 yuan, which can accommodate 45 people. If you are in charge of renting a car, what do you think is the most suitable way to rent a car? 195÷45=3 (car) … 15 (person) 120+ 150×3=570 (yuan) A: I think we should rent 1 minibus, 3. Uncle Zhang goes to work by bus on Mondays, Wednesdays and Fridays. On Tuesday and Thursday, she goes to work by bus and goes home by a friend's car. If Uncle Zhang takes a one-way bus fare of 1 yuan and a weekly ticket to 9 yuan, do you think it is cost-effective for Uncle Zhang to buy a weekly ticket? Why? (3×2+2)× 1=8 (yuan) A: Because 8 yuan is less than 9 yuan, it is not cost-effective. Mom bought 5 Jin of oranges and 4 Jin of bananas to go to 22 yuan. As we all know, the price of 3 kilograms of oranges is equal to the price of 2 kilograms of bananas. So how much are oranges and bananas per kilogram? 4 ÷ 2× 3 ÷ 5 =1.222 ÷ 2×1.2 ÷ 4 = 3.3 (yuan) 3.3×2÷3=2.2 (yuan) A: one catty of orange 2.2 yuan, one.