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In 2009, Beijing senior high school entrance examination mathematics 12 (I want to solve the problem! ! ! Don't answer)
1, triangle A'EB and triangle A'EB are congruent. A'B = AB = 1bn = 1/2.
According to Pythagorean theorem, a ′ n = (with 3)/2 can be obtained.
2. Like 1, AEB is congruent with triangle A 'eba 'b = AB =1BN =1-/n.
According to Pythagorean theorem, a ′ n = (2n-1)/n.