Although I can do it, this kind of topic is to improve the first grade of primary school, so don't be difficult for the child if he can't. Give it a try. Let's solve the problem from the point of view of primary school students.

At 1, the apple turns into a pear at the tenth place, which means that a single position enters one to ten places, so there are more pears than apples 1, and pears+pears are greater than 10, so pears may be 6, 7, 8 and 9. By trial and error, if the pear is 9, the number of apples will be less 1. Draw the conclusion that the apple is 8.

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Pear is 9, apple is 8.

2. Ten strawberries are bigger than peaches, so a peach-strawberry will return one, and it is concluded that strawberries are two bigger than peaches. Peaches MINUS strawberries are strawberries, and peaches should be even. It could be 2, 4, 6, 8, 0. Through the trial, when the peach is equal to 6, the strawberry will be twice as big as the peach. That's eight.

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Peach 6, strawberry 8.