p(X = 0)= c02c 3 13c 3 15 = 2235，

p(X = 1)= c 12c 2 13c 3 15 = 1235，

p(X = 2)= c22c 1 13c 3 15 = 135

Therefore, the distribution list of x is:

X 012p22351235135 (ii) e (x) =1×1235+2×135 = 25;

d(X)= 2235×(0-25)2+ 1235×( 1-25)2+ 135×(2-25)2 = 52 175。