In ▲AIB, IA+IB & gt；; ab blood type
In ▲AIC，ia+IC >； Alternating current
Because of AB> communication,
So: IA+IB & gt；; IA+IC
So: IB> integrated circuit
It can also be seen from the figure that IB is greater than IC, and the topic should be wrong.
Supplement 1: in ▲ABP, PA+PB & gt；; AB，
In ▲ACP，pa+PC >； Alternating current
In ▲BCP, PC+PB & gt；; B.C.
Because of AB & gtAC, PB> personal computers.
Because AB> is BC, PA> personal computer.
So PA+PB & gt；; 2PC> personal computer
2.In ▲ABD，a b+BD & gt； advertisement
In ▲ACD，AC+CD >； advertisement
In ▲BCE, BC+CE & gt；; exist
In ▲BAE，a b+ AE & gt； exist
In ▲BCF，BC+BF & gt； padre
In ▲ACF，AC+AF >； padre
Add up the above six inequalities, 3 (AB+BC+CA) >; 2(AD+BE+CF)
Namely: 2 (ad+be+cf) < 3(AB+BC+CA)