In ▲AIB, IA+IB & gt;; ab blood type
In ▲AIC,ia+IC >; Alternating current
Because of AB> communication,
So: IA+IB & gt;; IA+IC
So: IB> integrated circuit
It can also be seen from the figure that IB is greater than IC, and the topic should be wrong.
Supplement 1: in ▲ABP, PA+PB & gt;; AB,
In ▲ACP,pa+PC >; Alternating current
In ▲BCP, PC+PB & gt;; B.C.
Because of AB & gtAC, PB> personal computers.
Because AB> is BC, PA> personal computer.
So PA+PB & gt;; 2PC> personal computer
2.In ▲ABD,a b+BD & gt; advertisement
In ▲ACD,AC+CD >; advertisement
In ▲BCE, BC+CE & gt;; exist
In ▲BAE,a b+ AE & gt; exist
In ▲BCF,BC+BF & gt; padre
In ▲ACF,AC+AF >; padre
Add up the above six inequalities, 3 (AB+BC+CA) >; 2(AD+BE+CF)
Namely: 2 (ad+be+cf) < 3(AB+BC+CA)