(1) Because ac= 12 and AO=6, the square root of DO= 10 -6 is 8, so BD= 16.

(2) Because ⊙P and ⊙D are tangent, the radii are PO and DO respectively.

When ⊙P with radius PO is tangent to ⊙D with radius DF, DF=DO=8.

And triangle DFP and DOA, * * * angle FDO, right angles are equal, and side DF=DO, so triangle DFP and DOA are congruent, so side FP=AO=6, so side x= 16-√ 100=6.