∴a=2

Substitute the original formula and you get b=-3.

∴ 1/(√a-√|b|)= 1/(√2-√3)=(√2+√3)/ 1=√2+√3

13 、√| 4x-4y+ 1 |≥0，√(2y+z)≥0

∴ Z 2-Z+ 1/4 = 0, and the solution is z= 1/2.

∫2y+z = 0，4x-4y+ 1=0。

∴y=- 1/4,x=- 1/2

∴(y+z)x^2= 1/4× 1/4= 1/ 16

14, this question is misprinted, and one of the x should be written as y, no matter which result it is.

Judging from the meaning of the question, 3√(3x-7)=-3√(3y+4).

∴3x-7=-(3y+4)

If you move the item, you get 3x+3y=3.

∴x+y= 1

To learn to use the nature of absolute value and irrational number formula, as long as you know that the result in the formula must be greater than or equal to 0, the first two questions will be done well. The third question, you know, is that both sides are cubes and the process still holds.