This question should be calculated from the back to the front. Let's reverse the steps:

The last time-the maid got 1, and the four sons got n, ***4n+ 1 (the following ideas are basically the same).

The distribution of the old four-the old four gets (4n+ 1)/3, * * 4 (4n+1)/3+1=16n/3+7/3.

Old distribution-* * * 4 (16n/3+7/3)/3+1= 64n/9+37/9.

Second allocation-* * * 4 (64n/9+37/9)/3+1= 256n/27+175/27.

Boss distribution-* * * 4 (256n/27+175/27)/3+1=1024n/81+78/kloc-0.

Expand to obtain

That is, find the smallest n so that 1024n+78 1 is divisible by 8 1, while 1024 and 78 1 are divisible by 8 1, so n=80.

At least 8270 1 silver.