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The problem of the small champion in Huanggang, the second volume of mathematics in grade six.
Solution: (1) l = 2 * (r+h) * 2+18 = 2 * (10+90) * 2+18 = 418cm.

(2) The required iron sheet is at least larger than the surface area of the gift box, so S = π R2 * h+2π R2 = 3.14 *100 * 90+3.14 *100 * 2 = 28888 square centimeters.