Simple analysis: the probability of the three is completely equal, and the final result should be completely consistent, namely 1/3.

Specific situation

At first, A was the referee:

If the first game is B and C, then the second game A must be on the court.

If the referee was in the fourth game, then the third game must have been on the court and lost the game.

knowable

The first game: whether winning or losing, A must play.

Game 2: A must win.

Game 3: A must lose.

A The probability of being a referee is1*1/2 *1/2 =1/4.

At first, A was not the referee:

This is equivalent to the probability that B is not a referee at first and finally a referee (1- 1/4)/2=3/8.

Finally, the probability that A is the referee is1/3 *1/4+3/8 * 2/3 =1/3. End. ...