A∪B={x|x=2k or 2k- 1, k∈Z}
={x|x=k,k∈Z}
that is
A∪B=Z
For this problem, first observe two groups, because k belongs to an integer, a.
X=2K
No matter what value k takes, it must be an even set, B.
X=2K- 1, no matter what value K takes, it is a set of set numbers (if you don't understand it, you can use special value substitution method to verify it), then the union of A and B must be the sum of even and odd numbers, that is, all integers Z.
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