(4x^2-4x+ 1)+(y^2-6y+9)=0
(2x- 1)^2+(y-3)^2=0
Therefore, x = 1/2 and y = 3.
(2/3x√9x+y2√x/y3)-(x2√ 1/x-5x√y/x)
=2x√x+√xy-x√x-5√xy
=x√x-4√xy
=√2/4-2√6
=(√2-8√6)/4