1. Because ABC is an equilateral triangle with angle BAC=60 degrees, AD bisects angle EAC and bd bisects angle ABC, the angle DAB is equal to 120 degrees and the angle ABD is equal to 30 degrees. According to the theorem of internal angle sum, the angle ADB= 180- angle DAB- angle Abd = 188.

2. Let angle B be equal to X degree, angle C be equal to Y degree, and AC and BD intersect with point O, which can be obtained from the theorem of diagonal equality, the theorem that the sum of angles in a triangle is equal to 180 degree and the meaning of the question.

Angle EAC=X+Y Angle AOD= Angle BOC Angle DBC=X/2 Angle DAC=(x+y)/2.

The equation (x+y)/2+ angle d = x/2+y is obtained.

The angle D=Y/2, so: ∠ c = 2 ∠ d.