The thinking method of multiple solutions to one problem in junior high school mathematical geometry and another example of triangle

Answer according to the meaning of the question

Drawing design

In triangle abc

Bd and ce are known as ac respectively.

Median line of ab side

therefore

Parallel BC

(midline theorem)

And bd is perpendicular to ce.

bd=4

ce=6

So the area of trapezoid edcb =ecxdb/2= 12.

A triangular aed is similar to a triangular abc.

So ae/ab= 1/2, so s△aed/s△abc= 1/4, so S △ AED = X.

have

x/(x+ 12)= 1/4

x=4

solve

s△aed=4

therefore

Area of triangle abc = 16

Hope to adopt

thank you

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